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a^p=b^q=C^r=abc then pqr=?
We have:Hence,
a^p=abc so a=(abc)^1/psimilarly b=(abc)^1/qand c=(abc)^1/rtherefore abc = (abc)^1/p+1/q+1/r=> 1=(p+q+r)/(pqr)=> pqr = p+q+r
Given that a^p=abc so a=(abc)^1/pSimilarly b=(abc)^1/q and c=(abc)^1/rNow abc=(abc)^1/p.(abc)^1/q.(abc)^1/r=>abc=(abc)^1/p+1/q+1/r=>1=1/p+1/q+1/r=>1=(qr+pr+pq)/pqr=>pqr=pq+qr+rp
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