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A metal wire of length L is suspended vertically from a rigid support . When a Bob of mass M is attached to the lower end of the wire the elongation of the wire is l:Finda) the elastic constant of the wireB) heat produced during extension
one year ago

Dibyakanti Kumar
59 Points

(a)elastic constant =M*g/l [since Force by wire = elastic constant *l=M*g]
l is the elongation which means it is the change in length .
(b)Heat produced must be due to work done against gravity while extension of the wire .
Therefore Heat produced = 0.5*elastic constant*[(L+l)^2 – L^2] .
which can be derived by
integrating (elastic constant) *(length of wire at that moment) * dx from L to L+l .
one year ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions