A man standing at the top of a building throws a ball vertically upward with a velocity of 10 ms– 1 . The ball reaches the ground 4 s later. What is the maximum height reached by the ball? How high is the building

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Ananya · Answer

Since time taken to reach ground=4s Time taken to reach max hgt.=2s We know s=ut+1/2at² H(max)=10*2-1/2*9.8*2*2 =20-19.6=0.4m

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A man standing at the top of a building throws a ball vertically upward with a velocity of 10 ms– 1 . The ball reaches the ground 4 s later. What is the maximum height reached by the ball? How high is the building

A man standing at the top of a building throws a ball vertically upward with a velocity of 10 ms– 1 . The ball reaches the ground 4 s later. What is the maximum height reached by the ball? How high is the building

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A man standing at the top of a building throws a ball vertically upward with a velocity of 10 ms– 1 . The ball reaches the ground 4 s later. What is the maximum height reached by the ball? How high is the building

A man standing at the top of a building throws a ball vertically upward with a velocity of 10 ms– 1 . The ball reaches the ground 4 s later. What is the maximum height reached by the ball? How high is the building

1 Answers

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