A man running on a horizontal road at 8km/h finds the rain falling vertically .he increases his speed to 12km/h and find that the dropes make angle 30°with the vertical .find the speed and direction of the rain with respect to the road .

Question

Arun · Answer

Since when the person runs at 8 km/h the rain seems to be coming verticaly down thus the horizontal component of rain, Vx is 8 km/h When he incrreases his relative speed by 4 km/h with the horizontal component of rain, it seems to fall at an angle of 30 degrees with the vertical. It means the vertical component, Vy is: 4/Vy = tan 30 i.e. Vy = 6.93 km/h V = 10.58 km/h and angle of falling is: tan-1(8/6.93)

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A man running on a horizontal road at 8km/h finds the rain falling vertically .he increases his speed to 12km/h and find that the dropes make angle 30°with the vertical .find the speed and direction of the rain with respect to the road .

A man running on a horizontal road at 8km/h finds the rain falling vertically .he increases his speed to 12km/h and find that the dropes make angle 30°with the vertical .find the speed and direction of the rain with respect to the road .

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A man running on a horizontal road at 8km/h finds the rain falling vertically .he increases his speed to 12km/h and find that the dropes make angle 30°with the vertical .find the speed and direction of the rain with respect to the road .

A man running on a horizontal road at 8km/h finds the rain falling vertically .he increases his speed to 12km/h and find that the dropes make angle 30°with the vertical .find the speed and direction of the rain with respect to the road .

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