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A MAN MOVES IN AN OPEN FIELD SUCHB THAT AFTER MOVING 10M ON A STRAIGHT LINE, HE MAKES A SHARP TURN OF 60 TO HIS LEFT. THE TOTAL DISPLACEMENT JUST AT THE START OF 8TH TURN IS EQUAL TO
Displacement would be 20m as when a person changes his direction after every 10m at 60 degree angle so he will make an hexagon after 6 turns ie back to his original position and if he takes 2 more turns his displacement would be 20m
This is 10 m becase after completing a regular hexagon the man takes the last 2 turns and thus form an equilataral triangle of which one side is the displacement.and hence the answer will be 10 m
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