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`        A man is at a distance of 6m from a bus. The bus begins to move with a constant acceleration of 3m/s2. In order to catch the bus, the minimum speed with which the man should run towards the bus is :(a) 2 m/s(b) 4m/s© 6m/s(d) 8m/s`
one year ago

Khimraj
3008 Points
```							let speed is vthen to catch bus6 + ½*3*t2 = v*t3t2 -2vt + 12 = 0Now the logic is simple, the passenger will catch the bus after a certain time. So the passenger can catch the bus only when time is a real number. So the quadratic equation must give t as a real number.For that the discriminant (D) of the equation must be greater than or equal to zero.4v2 – 4*3*12 >=0for min velocityv2 = 36v = 6 m/sHope it clears. If you Like answer then please approve the  answer.
```
one year ago
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### Course Features

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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions