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`        a large boulder is ejected vertically upward from a volcano with an initial speed of 40.0m/sec. Air resistance may be ignored`
2 years ago

Arun
23742 Points
```							Dear Studentyour question is in complete.but I have solved the question somewhere so here I am again solvingA large boulder is ejected vertically upward from a volcano with an initial speed of 40.0 m/s. Air resistance may be ignored. (a) At what time after being ejected is the boulder moving at 20.0 m/s upward? (b) At what time is it moving at 20.0 m/s down-ward? (c) When is the displacement of the boulder from its initial position zero? Solution  (a) V = Vo + at 20 = 40 - 9.8*t → t = 2.04 s (b) -20 = 40 - 9.8*t → t = 6.12 s (c) s = 0 = Vo*t + ½at² = (Vo + ½at) * t So one solution is obviously t = 0 s. The other is 0 = 40 - ½ * 9.8m/s² * t → t = 8.16 s == OR == find out when its velocity is -40 m/s: -40 = 40 - 9.8*t RegardsArun (askIITians forum expert)
```
2 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions