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Grade: 11
        
A hemispherical bowl just floats without sinking in a liquid of density 1.2*103kg m-3 . I am outer diameter and density of the bowl are 1 m and 2*10kg m-3 respectively, then the inner diameter of bowl will be?? (FLUID STATICS)
one year ago

Answers : (2)

Arun
20387 Points
							
Dear student
 
I am getting innner dia d = 0.98 m
Let me know, if this is the right answer than I will.post the solution.
 
Regards
Arun (askIITians forum expert)
one year ago
Rishesh Gangwar
31 Points
							
    Weight of the bowl = mg                    = 
Vρg
=43π[(D2)3(d2)3]ρg
 where D = Outer diameter , d = Inner diameter 
ρ
 = Density of bowl                                  Weight of the liquid displaced by the bowl 
=Vσg
=43π(D2)3σg
 where 
σ
 is the density of the liquid.                                 For the flotation  
43π(D2)3σg=43π[(D2)3(d2)3]ρg
                                 Þ 
(12)3×1.2×103=[(12)3(d2)3]2×104
 By solving we get d = 0.98 m.
4 months ago
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