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        A hemispherical bowl just floats without sinking in a liquid of density 1.2*103kg m-3 . I am outer diameter and density of the bowl are 1 m and 2*104 kg m-3 respectively, then the inner diameter of bowl will be?? (FLUID STATICS)
one year ago

Arun
20387 Points
							Dear student

I am getting innner dia d = 0.98 m
Let me know, if this is the right answer than I will.post the solution.

Regards

one year ago
Rishesh Gangwar
31 Points
							    Weight of the bowl = mg                    = Vρg=43π[(D2)3−(d2)3]ρg where D = Outer diameter , d = Inner diameter ρ = Density of bowl                                  Weight of the liquid displaced by the bowl =Vσg=43π(D2)3σg where σ is the density of the liquid.                                 For the flotation  43π(D2)3σg=43π[(D2)3−(d2)3]ρg                                 Þ (12)3×1.2×103=[(12)3−(d2)3]2×104 By solving we get d = 0.98 m.

4 months ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions