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A heavy particle is suspended by a string of length l. The particle is given a horizontal velocity vo. The string becomes slack at some angle and the particle proceeds on a parabola. Find the value of v0 if the particle passes through the point of suspension
At a point when the particle is slackMgcos ω= m(v^2/l) here tension is zeroThen v^2=glcos........1ω where v is speed at point PUsing conservation of energy at point PV^2= v0^2-2gl(1+cosω)......2From equation 1 and 2 we getV0^2= gl(2+3 cosω).....3After breaking component we get tanω= 2^1/2From 3 we get. v0= {gl(2+3^1/2)}^1/2
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