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```
A gun of mass M fires a bullet of mass m with a kinetic energy E. The velocity of recoil of the gun is?

```
2 years ago

Susmita
425 Points
```							Gun and bullet were at rest initially.So initial momentum was zero.That means final momentum of the system must be zero.Let v be velocity of bullet and V be that of gun.So MV+mv=0Or,V=-mv/MKinetic energy of bulletE=(1/2)*mv2or,v=root(2E/m)So V=-(m/M)*root(2E/m)Please approve if helped.
```
2 years ago
Arun
25768 Points
```							Momentum before firing = 0 Momentum after firing = mv + MVAccording to law of conservation of momentum, mv + MV = 0Recoil velocity V = - mv /M
```
2 years ago
Aswanth
18 Points
```							 Gun and bullet were at rest initially.So initial momentum was zero.That means final momentum of the system must be zero.Let v be velocity of bullet and V be that of gun.So MV+mv=0Or,V=-mv/MKinetic energy of bulletE=(1/2)*mv2or,v=root(2E/m)So V=-(m/M)*root(2E/m)
```
one year ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions