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        a gun is moving  at a speed of 30m/s fires a bullet at an angle of 30o with a veocity of 150m/s relative to the gun.Find the distance between the gun and the bullet when it hits the ground.(g=10m/s2.)
one year ago

Arun
23487 Points
							 Vertical component of velocity = 150 sin 30o  = 75 m/secHorizontal component of velocity relative to gun = 150 cos 30o = 75√3 m/secHorizontal component of velocity relative to ground = 75√3 + 30 ≈ 160m/secTime of flight   = (275)/g = 15 sRange of projectile = 160 × 15 = 2400 mDistance moved by the gun and projectile = 2400 - 450 = 1950 m.

one year ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions