#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

# A cube of wood supporting 200 gm mass just floats in water. When the mass is removed. The cube ruses by   2 cm. What is the  size of the cube?

Kevin Nash
6 years ago
Hello Student,
Let the edge of cube be ℓ. When mass is on the cube of wood
200 g + ℓ3 d wood g = ℓ3 dwater g
⇒ ℓ3 dwood = ℓ3 dwater – 200 … (i)
When the mass is removed
3 dwood = (ℓ - 2 ) ℓ2 dwater … (ii)
From (i) and (ii)
3 dwater - 200 = (ℓ- 2) ℓ2 dwater
But dwater = 1
∴ ℓ3 - 200 = ℓ2 (ℓ - 2)
⇒ ℓ = 10 cm
Thanks
Kevin Nash
SHAIK AASIF AHAMED
6 years ago
Hello student,

Let the edge of the cube be x and the cube rises 2 cm on removing the mass. Thus, the weight of the body must be equal to the thrust provided by 2 cm height of the cube of base areas x2.

i.e. 200 g = (2 x2) 1 g

or x = 10 cm

Thanks and regards

Shaik Aasif

Gopivallabh
13 Points
3 years ago

# A CUBE OF wood floating in water supports 200g mass resting at centre of its toop face . when mass is removed, cube rises 2cm . find out volume of cube

Shreya
11 Points
2 years ago
Let the edge of the cube be l cmWe know that mass=density× volumeVolume=area of the cube×heightGiven the cube rises by 2cm hence ht=2cmSo L×L×2×1g=200gm(density of water=1gm)L×L=100So l=10cm
Rishi Sharma
9 months ago
Dear Student,

Let the edge of the cube be x
cube rises 2 cm on removing the mass.
Thus, weight of the body must be equal to the thrust
provided by 2 cm height of the cube of base areas x2.
i.e. 200 g = (2 x2) 1 g
or x = 10 cm
Thanks and Regards