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A cord is wound around the circumference of a wheel of diameter 0.3m.The axis of the wheel is horizontal.A mass of 0.5kg is attached at the end of the cord and it is allowed to fall from rest.If the weight falls 1.5m in 4s,what is the angular acceleration of the wheel?Also , find the moment of inertia of the wheel.

A cord is wound around the circumference of a wheel of diameter 0.3m.The axis of the wheel is horizontal.A mass of 0.5kg is attached at the end of the cord and it is allowed to fall from rest.If the weight falls 1.5m in 4s,what is the angular acceleration of the wheel?Also , find the moment of inertia of the wheel.                                                                                              

Grade:11

2 Answers

Arun
25750 Points
5 years ago
Dear student
 
Use
S = ut + 1/2 f t²
1.5 = 0 * t + 1/2 a (4)²
 
 
Hope it helps
 
Regards
Arun (askIITians forum expert)
Gourav
34 Points
5 years ago
S = ut + 1/2 at^2
3/2 = 0+ 1/2 a 4^2
a = 3/8 m/s^2
a=r alpha
alpha =a/r =(3/8)/1.5 = 5/4 rad s-^2
I = mr^2 =  0.5 * (0.3/2)^2

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