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Grade: 11
        
A cord is wound around the circumference of a wheel of diameter 0.3m.The axis of the wheel is horizontal.A mass of 0.5kg is attached at the end of the cord and it is allowed to fall from rest.If the weight falls 1.5m in 4s,what is the angular acceleration of the wheel?Also , find the moment of inertia of the wheel.                                                                                              
9 months ago

Answers : (2)

Arun
21522 Points
							
Dear student
 
Use
S = ut + 1/2 f t²
1.5 = 0 * t + 1/2 a (4)²
 
 
Hope it helps
 
Regards
Arun (askIITians forum expert)
9 months ago
Gourav
34 Points
							
S = ut + 1/2 at^2
3/2 = 0+ 1/2 a 4^2
a = 3/8 m/s^2
a=r alpha
alpha =a/r =(3/8)/1.5 = 5/4 rad s-^2
I = mr^2 =  0.5 * (0.3/2)^2
7 months ago
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