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`        A cord is wound around the circumference of a wheel of diameter 0.3m.The axis of the wheel is horizontal.A mass of 0.5kg is attached at the end of the cord and it is allowed to fall from rest.If the weight falls 1.5m in 4s,what is the angular acceleration of the wheel?Also , find the moment of inertia of the wheel.                                                                                              `
one year ago

Arun
23359 Points
```							Dear student UseS = ut + 1/2 f t²1.5 = 0 * t + 1/2 a (4)²  Hope it helps RegardsArun (askIITians forum expert)
```
one year ago
Gourav
34 Points
```							S = ut + 1/2 at^23/2 = 0+ 1/2 a 4^2a = 3/8 m/s^2a=r alphaalpha =a/r =(3/8)/1.5 = 5/4 rad s-^2I = mr^2 =  0.5 * (0.3/2)^2
```
one year ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions