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Grade: 11
        A bullet on penetrating 2 successive wooden planks of unqual thickness loses its velocity by 200meter per second in each case. If the initial velocity is 1000meter per second calculate the ratio of thickness of the Planks.
2 years ago

Answers : (2)

Eshan
askIITians Faculty
2095 Points
							Loss in kinetic energy of bulletthrough a block\proptothickness of the block.

Hence for the first block

\dfrac{1}{2}m(1000^2-200^2)\propto t_1

for the second block,

\dfrac{1}{2}m(200^2-0^2)\propto t_2

\implies \dfrac{t_1}{t_2}=\dfrac{1000^2-200^2}{200^2}=24
one year ago
Ankan Pal
15 Points
							
Initial velocity-1000 m/S
After penetrating 1st block final velocity -(1000-200)=800 m/S
For 2nd block initial velocity-800m/S
Final velocity-600 m/S
Now,
V1^2=u1^2-2as1
2as1=u^2-v^2.       _(1)
as1=18000
V2^2=u2^2-2as2
2as2=u2^2-v2^2
as2=14000.          _(2)
Now (1)÷(2)= as1÷as2=18000÷14000
S1:s2= 9:7
Hence the ratio of the thickness of the planks are 9:7
 
 
5 months ago
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