Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

a bullet of mass m moving horizontally with velocity v hits a block of wood of mass M resting on a smooth horizontal plane. The fraction of energy of the bullet dissipated in the collision itself is?

a bullet of mass m moving horizontally with velocity v hits a block of wood of mass M resting on a smooth horizontal plane. The fraction of energy of the bullet dissipated in the collision itself is?

Grade:12

1 Answers

Abhishek Singh
103 Points
6 years ago
after collision velocity of syst=v. = mv/(m+M)
initial energy=1/2mv2
Final energy= ½ (M+m)v’2
 
Energy lost = final – initial = ½ mv(M/M+m)
fractional energy lost= energy lost/initial energy= M/M+m

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free