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Grade: 12th
        A bullet of mass 20g is found to pass two points 30m apart in a time interval of 4sec. Calculate kinetic energy of the bullet,if it moves with a constant speed
2 years ago

Answers : (2)

Arun
23343 Points
							
 
velocity of bullet = 30/4 = 15/2
k.e = 20 *15*15 /(2*2*1000) =1.125 j 
where k.e is kinetic energy
j is joules 
 
velocity = distance / time 
2 years ago
Ruchika gupta
15 Points
							
V=s/t
V=30/4 = 7.5
Kinetic energy =1/2mv^2
Kinetic energy =1/2×0.02×7.5×7.5
Kinetic energy = 0.5625 joule 
4 months ago
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