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`        A bullet of mass 20g is found to pass two points 30m apart in a time interval of 4sec. Calculate kinetic energy of the bullet,if it moves with a constant speed`
2 years ago

## Answers : (2)

Arun
23343 Points
```							 velocity of bullet = 30/4 = 15/2k.e = 20 *15*15 /(2*2*1000) =1.125 j where k.e is kinetic energyj is joules  velocity = distance / time
```
2 years ago
Ruchika gupta
15 Points
```							V=s/tV=30/4 = 7.5Kinetic energy =1/2mv^2Kinetic energy =1/2×0.02×7.5×7.5Kinetic energy = 0.5625 joule
```
4 months ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions