A bomb of mass 1 kg, thrown vertically upwards with a speed of u=100m/sec, explodes into two parts after t=5 secs. A fragment of mass m1= 400 g moves downwards with a speed v1= 25 m/sec, then speed v2 and direction of another mass m2 will be-a) 40 m/s downwardsb) 40m/s upwardsc) 60m/s upwardsd) 100m/s upwards
Nivedita , 6 Years ago
Grade 11
1 Answers
Khimraj
Last Activity: 6 Years ago
velocity of bomb after 5 sec = 100 – 10*5 = 50 m/s
then applying conservation of momentum and taing upward direction as positive