Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
A body travel 100 m in the first 2 seconds and 104 m in the next 4 seconds .How far will it move in the next 4 seconds of the acceleration is uniform
From eqn. S=ut+1/2at^2For t=2,S=100 , solving this we get a relation between u &a as u+a=50.Acc. is uniform and it moves 104m in next 4 secAgain using the same eqn. Taking S=204(from the starting point) in time T=6sec .We get u+3a=36 . Solving these eqns we get u= 57 & a= -7.So the displacement covered in next 4 sec is S(at 10 sec from starting point)-S(at 6 sec) = -84 m.[But if you meant how much "distance they travel" u also need to consider the stopping point (I.e at 8.1428 sec for this case and at 232m for this prob. You get distance covered=140m)
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -