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A body of mass 5 kg is placed at the origin, and can move only on the x-axis. A force of 10 N is acting on it in a direction making an angle of o 60 with the x-axis and displaces it along the xaxis by 4 metres. The work done by the force is
Theta = 60 °Force = 10 NewtonDisplacement = 4 meter Work done = Force × Displacement × Cos / thetaW = 10 × 4 × 1 / 2W = 40 × 1 / 2W = 20 Joules
Dear student One thing is not clear in the above explanation is , Here we have taken component of displacement in x direction , It is xCosQ Q = 60 degree So W = FXCosQ = 20 Jule Hope ths will help Good Luck
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