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`        a body is thrown upwards with velocity of 100m/s and it travel 5m in the last second of its motion.if the same body is thrown upwards with a velocity of 200 m/s find the distance travelled by it in the last second of its journey`
2 years ago

Arun
23338 Points
```							Dear Ishan

For case2 there is no effect of case 1.
Now
V² = u² - 2gS
0 = 200² - 2* 10 * S
40000/20 = S
S = 2000 metres
V= u + g*t
0 = 200 - 10 * t
t = 20 sec
In last second distance,
S20 = u + (1/2) g *(2t-1)
= 200 - (1/2)*10* 39
= 200 - 195
= 5 metres

Regards
```
2 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions