A body is projected with a velocity u. It passes through a certain point above the ground after t1 sec . The time after which the body passes through the same point during the return of journey is : ?

Question

Arun · Answer

Let the starting point be A, point crossed by the ball be B and final point from where the ball returns be C.
For AC, v=0, u=u, and total time= t
0= u-gt
Or t= u/g ---eq.1
Now from A to B, time = t1 & from B to C, t= t2.
t = t1+t2 or t2 = t - t1.
But the ball comes back to the point B from C,
Implies that t2= 2(t- t1)
= 2(u/g - t1) is the final answer.

Khimraj · Answer

A body is projected upwards with a velocity u. It passes through a certain point above the ground after T1 second the time after which the body pass through the same point during the return journey is 2u/g - t1. t1 + t2= 2u / g So t2 = 2(u/g - t1)

aswanth nayak · Answer

Dear Student, A body is projected upwards with a velocity u. It passes through a certain point above the ground after T1 second the time after which the body pass through the same point during the return journey is 2u/g - t1. t1 + t2= 2u / g So t2 = 2(u/g - t1) Hope it helps you Regards

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A body is projected with a velocity u. It passes through a certain point above the ground after t1 sec . The time after which the body passes through the same point during the return of journey is : ?

A body is projected with a velocity u. It passes through a certain point above the ground after t1 sec . The time after which the body passes through the same point during the return of journey is : ?

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A body is projected with a velocity u. It passes through a certain point above the ground after t1 sec . The time after which the body passes through the same point during the return of journey is : ?

A body is projected with a velocity u. It passes through a certain point above the ground after t1 sec . The time after which the body passes through the same point during the return of journey is : ?

3 Answers

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