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`        A body  is projected with a velocity u. It passes through a certain point above the ground after t1 sec . The time after which the body passes through the same point during the return of journey is : ?`
one year ago

Arun
24739 Points
```							Let the starting point be A, point crossed by the ball be B and final point from where the ball returns be C. For AC, v=0, u=u, and total time= t0= u-gtOr t= u/g ---eq.1Now from A to B, time = t1 & from B to C, t= t2.t = t1+t2 or t2 = t - t1.But the ball comes back to the point B from C,Implies that t2= 2(t- t1)= 2(u/g - t1) is the final answer.
```
one year ago
Khimraj
3007 Points
```							A body is projected upwards with a velocity u. It passes through a certain point above the ground after T1 second the time after which the body pass through the same point during the return journey is 2u/g - t1. t1 + t2= 2u / g So t2 =  2(u/g - t1)
```
one year ago
aswanth nayak
100 Points
```							Dear Student, A body is projected upwards with a velocity u. It passes through a certain point above the ground after T1 second the time after which the body pass through the same point during the return journey is 2u/g - t1. t1 + t2= 2u / g So t2 =  2(u/g - t1) Hope it helps youRegards
```
11 months ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions