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`        A body fallung from tha rest has a velocity v after it falls through a height h . The distance it has to fall down further for its velocity to become double will be`
2 years ago

Arun
24497 Points
```							Dear Deepak Usev^2 – u^2 = 2*g*sintial velocity u=0at velocity=v height=hthereforeu^2 = 2ghthen let intial velocity u=vand final velocity=2vtherefore(2v)^2 – v^2 = 2*g*s4* v^2 – v^2 = 3 v^2 = 6*g*h = 2g* (3h)the distance it has to fall down further for its velocity to become 2v is 3.times h.  RegardsArun (askIITians forum expert)
```
2 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions