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A block of mass M = 5kg is resting on a rough horizontal surface for which the cofficient of friction is 0.2 . When a force F = 40N IS APLIED AS SHOWN IN THE FIGURE the aceleration of the block will be

  1. A block of mass M = 5kg is resting on a rough horizontal surface for which the cofficient of friction is 0.2 . When a force F = 40N IS APLIED AS SHOWN IN THE FIGURE the aceleration of the block will be 

Grade:11

2 Answers

Arun
25750 Points
4 years ago
 
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Vikas TU
14149 Points
4 years ago
Mass of block = 5kg
F = 40N
μ = 0.2
g = 10 m/s²
friction, f = μmg = 0.2×5×10 = 10N
net force =F-f = 40-10 = 30N
acceleration = 30/5 = 6m/s²

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