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`        	A block of mass M = 5kg is resting on a rough horizontal surface for which the cofficient of friction is 0.2 . When a force F = 40N IS APLIED AS SHOWN IN THE FIGURE the aceleration of the block will be `
6 months ago

Arun
23823 Points
```							 There is no image attached . Please check and repost the question with an attachment.I will be happy to help you
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6 months ago
Vikas TU
10605 Points
```							Mass of block = 5kgF = 40Nμ = 0.2g = 10 m/s²friction, f = μmg = 0.2×5×10 = 10Nnet force =F-f = 40-10 = 30Nacceleration = 30/5 = 6m/s²
```
6 months ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions