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A ball projected from ground vertically upward is at same height at time t1 and t2 .the speed of projection of ball is.

```
5 years ago

Shobhit
29 Points
```							Since particle is atsame height at time t1&t2, therefore,t1 + t2 = total time of flightt1 + t2 =2TT=t1+t2/2AlsoT=u/g from (v=u+at and v being 0 at maximum height and g is negative)Therefore u/g=T1+t2/2Or U=1/2g(t1+t2)
```
4 years ago
Soup tik Choudhury
13 Points
```							 Since particle is at same height at time t1&t2,Therefore,(t1 + t2)= total time of flight(t1 + t2) =2TT=(t1+t2)/2AlsoT=u/g from (v=u+at and v being 0 at maximum height and g is negative)Therefore,u/g=(t1+t2)/2u=g(t1+t2)/2
```
2 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions