MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 7
        A ball is thrown upward with a velocity of 29.4m/search. From a tower that is 98m/s: calculate 1.time it takes to reached the height point. 2. The height distance reached. 3. Time it takes to reached the ground. ( g-9.8m/s)
8 months ago

Answers : (1)

Rishav Ranjan
17 Points
							You can do it by a simple formulau=29m/s and g=9.8 m/s^21) now time to reach maximum height=u/g=29.4/9.8=3s.2) maximum height=u^2/g=29.4×29.4/2×9.8=44.1m3)total time=2u/g=2×29.4/9.8=6s.
						
8 months ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

Get Extra Rs. 276 off

COUPON CODE: SELF10


Course Features

  • 101 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 110 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Get Extra Rs. 297 off

COUPON CODE: SELF10

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details