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A ball is thrown horizontally from a cliff such that it strikes the ground after 5 seconds. The line of sight from the point of projection to the point of projection of hitting makes an angle of 37 degrees with the horizontal. What is the initial velocity of projection?
A ball is thrown horizontally from a cliff such that it strikes the ground after 5 seconds. The line of sight from the point of projection to the point of projection of hitting makes an angle of 37 degrees with the horizontal. What is the initial velocity of projection?


3 years ago

Arun
25768 Points
							Dear AditiWhen you make the diagram you will seeTan 37 = h/R3/4 = h/RR = 4 h/3AlsoT = $\LARGE \sqrt$(2h/g)5 = $\LARGE \sqrt$(2h/g)25 = 2h/gPut g = 10h = 125 metres NowR = u*Tu = R/T = 4*125/3*5u = 100/3 m/sec RegardsArun (askIITians forum expert)

3 years ago
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• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions