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A ball is dropped from a high rise platform at t=0 starting at rest.After 6 seconds another ball is thrown downwards from the same platform with speed v.The 2 balls meet at t=18s.What is the value of v?
A ball is dropped from a high rise platform at t=0 starting at rest.After 6 seconds another ball is thrown downwards from the same platform with speed v.The 2 balls meet at t=18s.What is the value of v?

```
3 years ago

Arun
25768 Points
```							Distance of 1st ball= S= 1/2 x 10 x 18 = 1620Distance of 2nd ball = S' = ut + 1/2gt²1620 = 12u + 5 x 144u = 135 - 60= 75 m/s
```
3 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions