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Grade: 12

                        

A ball is dropped from a high rise platform at t=0 starting at rest.After 6 seconds another ball is thrown downwards from the same platform with speed v.The 2 balls meet at t=18s.What is the value of v?

3 years ago

Answers : (1)

Arun
24741 Points
							
Distance of 1st ball= S= 1/2 x 10 x 18 
= 1620

Distance of 2nd ball = S' = ut + 1/2gt²
1620 = 12u + 5 x 144
u = 135 - 60
= 75 m/s
3 years ago
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