A 53-Ib (= 240-N) trunk rests on the floor. The coefficient of static friction between the trunk and the floor is 0.41, while the coefficient of kinetic friction is 0.32. (a) What is the mini- mum horizontal force with which a person must push on the trunk to start it moving? (b) Once moving, what horizontal force must the person apply to keep the trunk moving with constant velocity? (c) If, instead, the person continued to push with the force used to start the motion, what would be the acceleration of the trunk?

Question

Navjyot Kalra · Answer

Round off to two significant figures, f s = 98 N Therefore, the minimum horizontal force that just start moving the trunk is 98 N . Round off to two significant figures, f k = 77 N Therefore, the force that will keep the trunk moving with a constant velocity is 77 N. Therefore the force accelerating the trunk is 21.6 N . Therefore, the acceleration of the trunk is 0.88 m/s 2 .

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