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Grade: 11
        
A 50kg man is standing at one end of a 25m long boat.he starts running towards at the other end.On reaching the other end his velocity is 2m/s. If the mass of the boat is 200 kg , final velocity of the boat is?
 
 
10 months ago

Answers : (2)

Arun
21508 Points
							
 Momentum Before = Momentum After 
         0 = (50 Kg)  • (2 m/sec) + (50 + 200 Kg)  • (Vв) 
            Vв = -  2/5 m/sec 

 ... where the boat travels in the opposite direction of the runner.
10 months ago
SIDDHI AMRALE
28 Points
							
Here the external unbalanced force is 0, so the law of conservation of momentum can be applied.
Mass of man (Mm)=50
Mass of boat(Mb)=200
Velocity of man(Vm)=2
Velocity of boat(Vb)=?
External force=0
Hence, initial momentum is equal to final momentum
Pi=Pf
boat and man initially at rest
Pi=0
Pf= Pm + Pb
Here, final momentum will be 0 as initial momentum is 0
 
0= MmVm +( Mb+Mm)Vb
As mass of boat will also contain mass of man as man is standing on the boat
0=50×2+(200+50)Vb
-250 Vb = 100
Vb= -2/5
 
7 months ago
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