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A 4.88-kg object with a speed of 31.4 m/s strikes a steel plate at an angle of 42.0° and rebounds at the same speed and angle (Fig). What is the change (magnitude and direction) of the linear momentum of the object?

A 4.88-kg object with a speed of 31.4 m/s strikes a steel plate at an angle of 42.0° and rebounds at the same speed and angle (Fig). What is the change (magnitude and direction) of the linear momentum of the object?

Grade:11

1 Answers

Aditi Chauhan
askIITians Faculty 396 Points
8 years ago
The below figure shows a 4.88-kg object with a speed of 31.4 m/s strikes a steel plate at an angle of 42.0° and rebounds at the same speed with same angle which is shown geometrically.
236-346_1.JPG
The initial momentum of the object is pi when it strikes the steel plate.
To find initial momentum pi, substitute pi for p, 4.88-kg for mass m of the object and 31.4 m/s for velocity of the object in the equation p = mv,
pi = mv
= (4.88 kg) (31.4 m/s)
= 153 kg. m/s …… (2)
Since the final momentum pf of the object is equal to the initial momentum pi of the object, therefore,
pf = 153 kg. m/s …… (3)
In the above figure the angle θ will be,
θ = 42° + 42°
= 84°

236-1466_1.JPG

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