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A 10kg monkey is climbing a massless rope attached to a 15kg mass and is passing over a smooth pulley.The mass is lying on the ground.In order to raise the mass from the ground , the monkey must climb with an acceleration greater than...?
A 10kg monkey is climbing a massless rope attached to a 15kg mass and is passing over a smooth pulley.The mass is lying on the ground.In order to raise the mass from the ground , the monkey must climb with an acceleration greater than...?

```
3 years ago

Arun
25768 Points
```							Sum of forces on monkey = MA=T-Mg Sum of forces on banana box = ma=T-mg when the package goes from being on the ground to being lifted off the ground it's acceleration will change from 0 to some number, thus the minimum rope tension required will be just greater than T when a=0 ma=T-mg a=(T-mg)/m 0=(T-mg)/m T=mg=(15 kg)(9.8 m/s^2)=147 N MA=T-Mg A=(T-Mg)/M A=[147 N - (10 kg)(9.8 m/s^2)]/10 kg = 4.9 m/s^2
```
3 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions