0

Guest

Courses New

A 10kg monkey is climbing a massless rope attached to a 15kg mass and is passing over a smooth pulley.The mass is lying on the ground.In order to raise the mass from the ground , the monkey must climb with an acceleration greater than...?

A 10kg monkey is climbing a massless rope attached to a 15kg mass and is passing over a smooth pulley.The mass is lying on the ground.In order to raise the mass from the ground , the monkey must climb with an acceleration greater than...?

Grade:12

1 Answers

Arun
25750 Points
6 years ago
Sum of forces on monkey = MA=T-Mg Sum of forces on banana box = ma=T-mg when the package goes from being on the ground to being lifted off the ground it's acceleration will change from 0 to some number, thus the minimum rope tension required will be just greater than T when a=0 ma=T-mg a=(T-mg)/m 0=(T-mg)/m T=mg=(15 kg)(9.8 m/s^2)=147 N MA=T-Mg A=(T-Mg)/M A=[147 N - (10 kg)(9.8 m/s^2)]/10 kg = 4.9 m/s^2

Think You Can Provide A Better Answer ?

Other Related Questions on Mechanics

View all Questions ยป

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More