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A 1 kg block B rests as shown on a bracket A of same mass . Constant forces F1 = 20 N and F2=8N start to act at time t=0 when the distance of block B from pulley is 8m what is the time when block B reaches the pulley please tell me where i am doing wrong?????

A 1 kg block B rests as shown on a bracket A of same mass . Constant forces F1 = 20 N and F2=8N start to act at time t=0 when the distance of block B from pulley is 8m what is the time when block B reaches the pulley
 
 
please tell me where i am doing wrong?????

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Grade:12th pass

4 Answers

Abhishek
15 Points
5 years ago
It
Anmol
15 Points
4 years ago
Relative acceleration between block and bracket is 4m/s^2 
...Now we can use second equation of motion from where we got t=0.5sec
utkarsh sinha
14 Points
3 years ago
Total distance=0.5m                                                            
 
Net Force=12N
 
so force exerted by the wall on the string of the pulley=12N
 
so force exerted on block b=12/2=6N
 
so acceleration =6/1=6m/s^2
 
u=0
 
so dist=1/2at^2
 
0.5=3t^2
 
so time taken = 0.4 sec           (ans)
 
utkarsh sinha
14 Points
3 years ago
T= F2=8N
 
F1-2T=1*a
 
so a=4m/s^2 
 
so distance =0.5m
 
so,   0.5=1/2at^2
 
so, t^2=0.25
 
t=0.5sec   (ans) 
 
 
here, T=tension 
f1=20N         f2=8N

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