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Two identical trains A and B move with equal speeds on parallel tracks along the equator. A moves from east to west . and B moves from west to east. Which train will exert a greater force on the track. (1) A (2) B (3) they will exert equal force (4) the mass and the speed of each train must be known to reach a conclusion

Two identical trains A and B  move with equal speeds on parallel tracks along the equator. A moves from east to west . and B moves from west to east. Which train will exert a greater force on the track.


(1) A


(2) B


(3) they will exert equal force


(4) the mass and the speed of each train must be known to reach a conclusion

Grade:

2 Answers

Anurag Kishore
37 Points
11 years ago

Hi,

As we know earth rotates from west to east so the train B will have speed v+wr

where v is speed of train, w is angular velocity of earth, r is radius of earth.

On the other hand train A moves in opposite direction of earths rotation so its net velocity is v-wr

So net centrifugal force on B will be greater due to which it will exert less force on track.

So,

correct answer is (1)

S Ghosh
15 Points
2 years ago
Train moving in opposite direction of earth rotation is having Less angular velocity from frame of inertia. Now the required centripetal force here is equal to mg - N. Or N = mg - m .r. w.w . w is the angular velocity. So less is angular velocity more. is  the normal force , other parameters remain constant.  Hence train moving in opposite direction puts more normal force. 

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