Badiuddin askIITians.ismu Expert
Last Activity: 15 Years ago
Dear Amrit pal

dear consider a disk at a distance x of thickness dx whose outer radius is r' and inner radius is r/2
where x2 +r'2 = r2
r' =√(r2 -x2)
mass of the disk dm =ρ (πr'2 -π(r/2)2)dx where ρ is the dencity
dm =ρπ (r2-x2 -r2/4)dx
dm =ρπ (3r2/4 -x2 )dx
now center of mass = [0∫OC dm *x ]/ o∫OC dm
where OC =√(r2 -(r/2)2)
=r√3 /2
put the value and intigrate
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Badiuddin