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# a baloon of mass M is descending at constant acceleration s when a mass m is relased from the ballon it start raising with same acceleration s.assume tht its volume does not change whaty is value of m

10 years ago

Dear Jauneet Singh,

Let the force due to buoyancy be B.

In the first case the equation will be

Mg - B = Ms

In the second case the equation will be

B - (M-m)g = (M-m)s

Since the volume is unchanged, the force of Buoyancy remains unchanged as same amount of air is displaced even now and the new mass is (M-m)

Adding the two equations we get,

mg = (2M-m)s

or m(g+s)=2Ms

or m=2Ms/(g+s)

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Spandan Pratyush

one year ago
thanks bro

Let the force due to buoyancy be B.

In the first case the equation will be

Mg - B = Ms

In the second case the equation will be

B - (M-m)g = (M-m)s

Since the volume is unchanged, the force of Buoyancy remains unchanged as same amount of air is displaced even now and the new mass is (M-m)

Adding the two equations we get,

mg = (2M-m)s

or m(g+s)=2Ms

or m=2Ms/(g+s)