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A man raises a bucket of water of mass 10 kg from a well. When the bucket has risen 18 m, its velocity is 16 m/s. Work done by the man is (take g = 10 m/s2)

(A)    3080 J

(B)    1280 J

(C)    1380 J

(D)    1800 J

7 years ago

147 Points

Dear ishika

work done by man = increse in total energy of bucket

=mgh + 1/2 m v2

= 10*10*18   + 1/2  * 10 * 162

= 3080 j

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7 years ago
396 Points

Dear ishika,

since

work done = potential energy+ kinetic energy.

= mgh + 1/2(mv2)

= (10×10×18)+[1⁄2×(162)].

= 3080 J

Thanks ans regards

Akhilesh Shukla

7 years ago
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