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A 2kg stone at the end of a string 1m long is whriled in a vertical circle at a constant speed The speed of the stone is 4m/s The tension in the string will be 52N when the stone is

pallavi pradeep bhardwaj , 16 Years ago
Grade 12
anser 1 Answers
Badiuddin askIITians.ismu Expert

Dear pallavi

 

 

6916-1578_7662_untitled.JPG

T = mv2 /r  + mgcosx

52 = 2*16/1  + 2*10  cosx

cosx=1

x=0

so particle will be at lower most position.

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Last Activity: 16 Years ago
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