Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

A 2kg stone at the end of a string 1m long is whriled in a vertical circle at a constant speed The speed of the stone is 4m/s The tension in the string will be 52N when the stone is

A 2kg stone at the end of a string 1m long is whriled in a vertical circle at a constant speed The speed of the stone is 4m/s The tension in the string will be 52N when the stone is

Grade:12

1 Answers

Badiuddin askIITians.ismu Expert
147 Points
11 years ago

Dear pallavi

 

 

6916-1578_7662_untitled.JPG

T = mv2 /r  + mgcosx

52 = 2*16/1  + 2*10  cosx

cosx=1

x=0

so particle will be at lower most position.

Please feel free to post as many doubts on our discussion forum as you can.
 If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly.
 We are all IITians and here to help you in your IIT JEE  & AIEEE preparation.

 All the best.
 
Regards,
Askiitians Experts
Badiuddin

 

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free