Mechanics> circular motion...
a small particle of mass m atached with a light inextensible spring L is moving in a vertical circle .minimum velocity required for the particle to go around complete vertical circle at highest ponit is √gl.in the given case the particle is moving in complete vertical circle & ratio of it's maximum to minimum velocity is 2:1
What is the minimum velocity
a)4√gl/3
b)2√gl/3
c)√gl/3
d)3√gl/3
ans (B) 2√gl/3
1 Answers
In this problem, the given velocity(√gl ) is the minimum velocity required for the particle at its highest point to complete vertical circle.
Let, u & v be the velocity of the particle at its lowest and highest point respectively.
u : v = 2:1 => u = 2v.----------->(1)
according to work-energy theorem,
mg(2l) = (1/2)mu2 - (1/2)mv2 --------------->(2)
from eqns (1)& (2), we get v = (2/3)(√gl).
This is the minimum velocity of the particle in its complete circular motion in this present case.
Prepraring for the competition made easy just by live online class.
Full Live Access
Study Material
Live Doubts Solving
Daily Class Assignments
Three identical balls are placed on a frictionless
horizontal surface touching each other. They stick to
each other because of adhesive. Another ball of same
radius and mass m is placed over the void created by
the three balls. Find the forces applied by the balls
kept on the floor to each other if the system remains
in equilibrium.
Last Activity: 6 Months ago
A car loaded with water having total mass 1000 kg moves on a straight horizontal Road starting from rest under the action of a force of 100 Newton. The water spills throw a small hole in the bottom at a rate of 0.1 KG per second the velocity of cart after 300 seconds is nearly.
11
21
31
41
Last Activity: 6 Months ago
Last Activity: 3 Years ago
Last Activity: 3 Years ago
Last Activity: 3 Years ago
