A point mass starts moving in straight line with const.acceleration. After time t_o,the acceleration changes its sign, remaining the same in magnitude. Determine the time t from the beginning of motion in which the point mass returns to the initial position?

Dear Chilukuri

after t_o  velocity of particle =at_o  

Distance travell in time to

S1 =0 +1/2 a to²

Time taken from from Point B to C in forward motion is

v=u -at

0=ato -at

t= to

same time willl take to come from point c to b

and from motion B to A  time take is

S1 = at0 + 1/2 a t²

1/2 a to²   = at0 + 1/2 a t²

solve for t

t = ( √2 -1 )to

so total time  t = to +to +to +( √2 -1 )to

                        =( √2 +2 )to

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Please feel free to post as many doubts on our discussion forum as you can.
 If you find any question Difficult to understand - post it here and we will get you the

answer and detailed solution very quickly.
 We are all IITians and here to help you in your IIT JEE  & AIEEE preparation.

 All the best.
 
Regards,
Askiitians Experts
Badiuddin