Two particles of masses m1 and m2 in projectile motion have velocities v1 and v2 resp. at time t=0. They collide at t=t1. There velocities become v''1 and v''2 at time 2t1 while still moving in air. The value of (m1v''1+m2v''2)-(m1v1+m2v2) is

Question

naman sharma · Answer

First write V1 ad v2 etc i vector form . Now since during collision only iternal forces act so momentum will be conserved SO THE ANSWER TO YOUR QUESTIO IS 0.

Lokendra · Answer

The external force present here is gravity. So, change in momentum =F(2t)= (m1+m2)g(2t)

Jitesh Singh · Answer

talking in vectors we have,v1`=v1+gt0andv2`=v2 +gt0.there fore, value of(m1v``1+m2v``2)-(m1v1+m2v2) is equal to {m1(v1`-v1) + m2(v2`-v2)}.and so we have 2(m1+m2)gt0.as our final answer

tarun · Answer

in this question we will use the formula change in momentum = force * time since gravity is acting so force = (M1 + M2)g hence we can write (M1 + M2)g*2t

Aishita batra · Answer

Normally we neglect gravitational force while applying conservation of momentum but we haven`t done so here.why?

Harsh gupta · Answer

Fext=(m1+m2)/g= |(m1v1'+m2V2')-(m1v1-m2v2)|/(2t - 0) so the value of |(m1v1'+m2V2')-(m1v1-m2v2)|=2(m1+m2)gt

Thank you for registering.

Register Now and Win Upto 25% Scholorship for a Full Academic Year !

Enter Your Details

Registration done!

Guest

Two particles of masses m1 and m2 in projectile motion have velocities v1 and v2 resp. at time t=0. They collide at t=t1. There velocities become v''1 and v''2 at time 2t1 while still moving in air. The value of (m1v''1+m2v''2)-(m1v1+m2v2) is

Two particles of masses m1 and m2 in projectile motion have velocities v1 and v2 resp. at time t=0. They collide at t=t1. There velocities become v''1 and v''2 at time 2t1 while still moving in air. The value of (m1v''1+m2v''2)-(m1v1+m2v2) is

6 Answers

Think You Can Provide A Better Answer ?

Other Related Questions on Mechanics

ASK QUESTION

Answer and earn gift vouchers

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Complete Self Study Package designed by Industry Leading Experts

Live 1-1 coding classes to unleash the Creator in your Child

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Register Now & Win Upto 25% Scholorship

Thank you for registering.

Register Now and Win Upto 25% Scholorship for a Full Academic Year !

Enter Your Details

Registration done!

Guest

IIT JEE Courses

One Year IIT Programme

Two Year IIT Programme

Crash Course

NEET Courses

One Year NEET Programme

Two Year NEET Programme

One to One

School Board

Live Online classes

Class 11 & 12

Class 9 & 10

Class 6, 7 & 8

Test Series

JEE test series

NEET test series

C.B.S.E test series

Complete Self Study Packages

FULL COURSE

For class 12th

For class 11th

Two particles of masses m1 and m2 in projectile motion have velocities v1 and v2 resp. at time t=0. They collide at t=t1. There velocities become v''1 and v''2 at time 2t1 while still moving in air. The value of (m1v''1+m2v''2)-(m1v1+m2v2) is

Two particles of masses m1 and m2 in projectile motion have velocities v1 and v2 resp. at time t=0. They collide at t=t1. There velocities become v''1 and v''2 at time 2t1 while still moving in air. The value of (m1v''1+m2v''2)-(m1v1+m2v2) is

6 Answers

Think You Can Provide A Better Answer ?

Other Related Questions on Mechanics

ASK QUESTION

Answer and earn gift vouchers

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Complete Self Study Package designed by Industry Leading Experts

Live 1-1 coding classes to unleash the Creator in your Child

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Register Now & Win Upto 25% Scholorship