A stone is dropped from top of a tower. When it crosses a point 5m below the top, another stone is let to fall from a point 25m below the top. Both stones reach the bottom of tower simultaneously.Find the height of the tower.(g=10 m/s2)
Dear Chilukuri
tami taken to fall a distance 5 m by first stone
5=1/2 *g*t2
t=1 sec
let hight of tower is h
so motion of first stone
h= 1/2 * 10 * t2 .....................1
motion of second stone
h-25 =1/2 * 10 *(t-1)2 ...............2
put value of h from equation 1
t=3 sec
and h=45 m
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