Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

a horizontal force f=mg/3 is applied on the upper surface of a uniform cube of mass m and side a which is resting on rough horizontal surface having k=1/2(friction co eff)the distance between lines of action of mg and normal reaction is

a horizontal force f=mg/3 is applied on the upper surface of a uniform cube of mass m and side a which is resting on rough horizontal surface having k=1/2(friction co eff)the distance between lines of action of mg and normal reaction is

Grade:Upto college level

1 Answers

Badiuddin askIITians.ismu Expert
147 Points
11 years ago

Dear akash

 

6404-583_7662_untitled.JPG

 

maximum static friction force=mg/2 >mg/3

so only mg/3 static friction force will act

N=mg

moment balance about the center of the cube.

mg/3 *a/2  +mg/3 *a/2 = mg*0 +N *x

x=a/3


Please feel free to post as many doubts on our discussion forum as you can.
 If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly.
 We are all IITians and here to help you in your IIT JEE  & AIEEE preparation.

 All the best.
 
Regards,
Askiitians Experts
Badiuddin

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free