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a horizontal force f=mg/3 is applied on the upper surface of a uniform cube of mass m and side a which is resting on rough horizontal surface having k=1/2(friction co eff)the distance between lines of action of mg and normal reaction is
Dear akash
maximum static friction force=mg/2 >mg/3
so only mg/3 static friction force will act
N=mg
moment balance about the center of the cube.
mg/3 *a/2 +mg/3 *a/2 = mg*0 +N *x
x=a/3
All the best. Regards, Askiitians Experts Badiuddin
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