a horizontal force f=mg/3 is applied on the upper surface of a uniform cube of mass m and side a which is resting on rough horizontal surface having k=1/2(friction co eff)the distance between lines of action of mg and normal reaction is

Question

Badiuddin askIITians.ismu Expert · Answer

Dear akash

maximum static friction force=mg/2 >mg/3

so only mg/3 static friction force will act

N=mg

moment balance about the center of the cube.

mg/3 *a/2 +mg/3 *a/2 = mg*0 +N *x

x=a/3

Please feel free to post as many doubts on our discussion forum as you can.
If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly.
We are all IITians and here to help you in your IIT JEE & AIEEE preparation.

All the best.

Regards,
Askiitians Experts
Badiuddin

Thank you for registering.

Register Now and Win Upto 25% Scholorship for a Full Academic Year !

Enter Your Details

Registration done!

a horizontal force f=mg/3 is applied on the upper surface of a uniform cube of mass m and side a which is resting on rough horizontal surface having k=1/2(friction co eff)the distance between lines of action of mg and normal reaction is

a horizontal force f=mg/3 is applied on the upper surface of a uniform cube of mass m and side a which is resting on rough horizontal surface having k=1/2(friction co eff)the distance between lines of action of mg and normal reaction is

1 Answers

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

Other Related Questions on Mechanics

ASK QUESTION

Answer and earn gift vouchers

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Complete Self Study Package designed by Industry Leading Experts

Live 1-1 coding classes to unleash the Creator in your Child

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Register Now & Win Upto 25% Scholorship