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Grade 12Mechanics

A lift whose floor to ceiling distance is 2.7 m,starts from rest and ascend with a constant acceleration of 1.2 m s^-2.two seconds later,a particle drops from the ceiling of the lift.caalculate the time taken by the partcle to hit the floor of the lift.

Profile image of Keerthana Mohan
13 Years agoGrade 12
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4 Answers

Profile image of mohit yadav
13 Years ago

1.5 sec

Profile image of Madhukar  Thalore
13 Years ago

The time taken will be approx. 1 second.

Profile image of FITJEE
13 Years ago

1.5

Profile image of SOURAV MISHRA
13 Years ago

let us solve the question from the frame of reference of the lift.

the net downward acceleration of the particle realtive to the lift is g + 1.2 m/s2.

then we can write 2.7 = (g + 1.2)t2/2.

we take g = 9.8 m/s2. this gives t = 0.7s.