A 20 gm ball is shot from a spring gun whose spring constant is 400 N/m.The spring is compressed by 5 cm. The maxmimum possible horizontal range of the ball for this compression is {g=10m/s}.
1/2kx^2=1/2mv^2
solving we get v^2=50
max range=v^2/g=5m
(1/2)kx2 = (1/2)mv2
the maximum range is given by v2/g = kx2/mg = 400*0.05*0.05/0.02*10 = 5m.
Three identical balls are placed on a frictionless
horizontal surface touching each other. They stick to
each other because of adhesive. Another ball of same
radius and mass m is placed over the void created by
the three balls. Find the forces applied by the balls
kept on the floor to each other if the system remains
in equilibrium.
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A car loaded with water having total mass 1000 kg moves on a straight horizontal Road starting from rest under the action of a force of 100 Newton. The water spills throw a small hole in the bottom at a rate of 0.1 KG per second the velocity of cart after 300 seconds is nearly.
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Last Activity: 9 Months ago
Last Activity: 3 Years ago
Last Activity: 3 Years ago
