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A 20 gm ball is shot from a spring gun whose spring constant is 400 N/m.The spring is compressed by 5 cm. The maxmimum possible horizontal range of the ball for this compression is {g=10m/s}.
1/2kx^2=1/2mv^2
solving we get v^2=50
max range=v^2/g=5m
(1/2)kx2 = (1/2)mv2
the maximum range is given by v2/g = kx2/mg = 400*0.05*0.05/0.02*10 = 5m.
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