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following sets of the three forces act on a body,. In which case resultant cannot be zero?
1) 10N, 10N, 10N
2)10N, 10N, 20N
3)10N, 20N, 20N
4010N, 20N, 40N
Dear Nandini,
In 1st case, if 10N and 10N are at 1200 then resultant of these two is 10N. Then the 3rd force if acted opposite to the resultant then net force is zero.
In 2nd case, if 10N and 10N are in same direction and 20N is opposite to both of them then resultant is zero.
In 3rd case, if 10N and 20N are acted at an angle of cos-1(-1/4) then the resultant is 20N. Then the third force if acted opposite to the resultant then net force is zero.
Explanation of third case: R2 = P2+Q2+2PQcosΘ ; (20)2 = (10)2+(20)2+2*10*20*cosΘ
Therefore cosΘ = (400 - 500)/400 = -1/4. This is possible value of cosΘ as it lies in the interval [-1,1].
Any such situation is not possible in 4th case. Hence, the resultant cannot be zero in 4th case.
in 3rd & 4th case.
In 4th case
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