#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

# A simple harmonic oscillator has a period of 0.01 sec and an amplitude of 0.2m The magnitude of the velocity in m/sec at the centre of oscillation is

Grade:12

## 2 Answers

Rohith Gandhi
24 Points
11 years ago

Dear Pallavi,

Please feel free to post as many doubts on our discussion forum as you can. If you find any question
Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We
are all IITians and here to help you in your IIT JEE preparation.

All the best Pallavi !!!

Regards,

Askiitians Experts

Rohith Gandhi P

Anas
13 Points
3 years ago
$\dpi{120} \fn_phv Velocity(max)= Amplitude into omega V(max)= A into 2pie/t V(max)= 0.2 into 2 pie/0.01 V(max)= 0.2 into 200 pie V(max)= 40pie (Answer)$

## ASK QUESTION

Get your questions answered by the expert for free