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A thin spherical shell of mass M , and radius R , has a small hole. A particle of mass m , is released at the mouth of the hole. Then: (A) The particle will execute SHM , inside the shell. (B) The particle will oscillate inside the shell, but the oscillations, are not simple harmonic. (C)particle will not oscillate, but the speed of particle will go on increasing. (D)none of these.

A thin spherical shell of mass M, and radius R, has a small hole. A particle of mass m, is released at the mouth of the hole. Then:


(A) The particle will execute SHM, inside the shell.


(B) The particle will oscillate inside the shell, but the oscillations, are not simple harmonic.


(C)particle will not oscillate, but the speed of particle will go on increasing.


(D)none of these.

Grade:11

2 Answers

Naman Arora
25 Points
8 years ago

first of all, is the shell hollow? or its a solid sphere?

if hollow, then it will be in oscillatory motion, not shm.

if solid(this is like u can move a stick past thru it), then it fill simply come out of the other end.... BUT if the solid sphere is the earth... then shm will happen(due to gravity acting at both ends)

so, seeing this question, and considering the SHELL as what it is called(shell means hollow,of course) the answer is B.......

plz leave a positive reply if satisfied

thanks

Sudeepan Datta
16 Points
8 years ago

but, within a hollow spherical shell, net gravitational field=0, then ain''t the answer ought to be (C)?

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