Mechanics> mechanics...
A car starting from rest accelerates at the rate f through a distance S, then continues
at constant speed for time t and then decelerates at the rate f/2 to come to rest. If the
total distance traversed is 15 S, then S=?
4 Answers
S=(ft^2)/2
V.=squere root of(2Sf)
During retardation S2=2S
During constant velocity 15S -3S = 12S = vo
. '' .S= (ft^2)/72
Approved
pl. approve if it helped,,,
S=(ft^2)/2
V.=squere root of(2Sf)
During retardation S2=2S
During constant velocity 15S -3S = 12S = vo
. '''' .S= (ft^2)/72
Approved
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