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A car starting from rest accelerates at the rate f through a distance S, then continues at constant speed for time t and then decelerates at the rate f/2 to come to rest. If the total distance traversed is 15 S, then S=?

A car starting from rest accelerates at the rate f through a distance S, then continues 
at constant speed for time t and then decelerates at the rate f/2 to come to rest. If the 
total distance traversed is 15 S, then S=?

Grade:11

4 Answers

upender surepally
126 Points
8 years ago

S=(ft^2)/2

V.=squere root of(2Sf)

During retardation S2=2S

During constant velocity  15S -3S = 12S = vo

. '' .S= (ft^2)/72

ankitesh gupta
63 Points
8 years ago

2487_74742_001.jpg

pl. approve if it helped,,,

naveen d
34 Points
8 years ago

S=(ft^2)/2

V.=squere root of(2Sf)

During retardation S2=2S

During constant velocity  15S -3S = 12S = vo

. '''' .S= (ft^2)/72

Yash Chourasiya
askIITians Faculty 256 Points
11 months ago
Hello Student

Please see the solution in the attachment
643-220_Untitled.png

I hope this answer will help you.

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