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Grade 11Mechanics

A car starting from rest accelerates at the rate f through a distance S, then continues
at constant speed for time t and then decelerates at the rate f/2 to come to rest. If the
total distance traversed is 15 S, then S=?

Profile image of shiva S
13 Years agoGrade 11
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4 Answers

Profile image of upender surepally
ApprovedApproved Tutor Answer13 Years ago

S=(ft^2)/2

V.=squere root of(2Sf)

During retardation S2=2S

During constant velocity  15S -3S = 12S = vo

. '' .S= (ft^2)/72

Profile image of ankitesh gupta
13 Years ago

2487_74742_001.jpg

pl. approve if it helped,,,

Profile image of naveen d
ApprovedApproved Tutor Answer13 Years ago

S=(ft^2)/2

V.=squere root of(2Sf)

During retardation S2=2S

During constant velocity  15S -3S = 12S = vo

. '''' .S= (ft^2)/72

Profile image of Yash Chourasiya
6 Years ago
Hello Student

Please see the solution in the attachment
643-220_Untitled.png

I hope this answer will help you.