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A car starting from rest accelerates at the rate f through a distance S, then continues at constant speed for time t and then decelerates at the rate f/2 to come to rest. If the total distance traversed is 15 S, then S=?
S=(ft^2)/2
V.=squere root of(2Sf)
During retardation S2=2S
During constant velocity 15S -3S = 12S = vo
. '' .S= (ft^2)/72
pl. approve if it helped,,,
S=(ft^2)/2 V.=squere root of(2Sf) During retardation S2=2S During constant velocity 15S -3S = 12S = vo . '''' .S= (ft^2)/72
. '''' .S= (ft^2)/72
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