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Grade 12Mechanics


ASSUME THE EARTH'S ORBIT AROUND THE AS CIRCULAR AND THE

SUN AS CIRCULAR AND THE DISTANCE BETWEEN THEIR CENTRES AS 'D'. MASS OF THE EARTH IM 'M' AND IT,S RADIUS IS 'R'.IF THE EARTH HAS AN ANGULAR VELOCITY 'ω'WITH RESPECT TO IT'S CENTRE AND 'Ψ' WITH RESPECT TO CENTRE OF THE SUN THE TOTAL KINETIC ENERGY OF EARTH IS.

1) MR2 ω2/5 [1+(Ψ/ω)2 +5/2(Dψ/Rω)2 ].

2) MR2 ω2/5 [1+5/2(Dψ/Rω)2 ]

3) 2/5MR2 ω2 [1+5/2(Dψ/Rω)2]

Profile image of DILIP MARPU
16 Years agoGrade 12
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1 Answer

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ApprovedApproved Tutor Answer1 Year ago

To determine the total kinetic energy of the Earth in this scenario, we need to consider both its rotational and translational motions. The Earth is not only rotating around its own axis but also revolving around the Sun. Let's break down the components of kinetic energy involved here.

Understanding Rotational and Translational Kinetic Energy

The total kinetic energy (KE) of an object can be expressed as the sum of its rotational kinetic energy and translational kinetic energy. The formulas for these energies are as follows:

  • Rotational Kinetic Energy (KE_rot): This is given by the formula:
  • KE_rot = (1/2) I ω²

  • Where I is the moment of inertia and ω is the angular velocity.
  • Translational Kinetic Energy (KE_trans): This is given by:
  • KE_trans = (1/2) m v²

  • Where m is the mass and v is the linear velocity.

Calculating the Rotational Kinetic Energy

For the Earth, the moment of inertia (I) can be approximated as:

I = (2/5) m R²

Thus, the rotational kinetic energy becomes:

KE_rot = (1/2) * (2/5) m R² ω² = (1/5) m R² ω²

Calculating the Translational Kinetic Energy

Next, we need to consider the translational kinetic energy due to the Earth's orbit around the Sun. The linear velocity (v) of the Earth can be expressed in terms of its angular velocity with respect to the Sun (Ψ) and the distance D from the Sun:

v = D Ψ

Substituting this into the translational kinetic energy formula gives:

KE_trans = (1/2) m (D Ψ)² = (1/2) m D² Ψ²

Combining the Energies

Now, we can combine both components to find the total kinetic energy of the Earth:

Total KE = KE_rot + KE_trans

Total KE = (1/5) m R² ω² + (1/2) m D² Ψ²

Expressing in Terms of Angular Velocities

To express the total kinetic energy in a more unified form, we can factor in the ratio of the angular velocities:

Let’s define the ratio:

x = Ψ / ω

Then, we can rewrite the translational kinetic energy as:

KE_trans = (1/2) m D² (ω x)² = (1/2) m D² ω² x²

Now, substituting this back into the total kinetic energy expression gives us:

Total KE = (1/5) m R² ω² + (1/2) m D² ω² x²

Final Expression for Total Kinetic Energy

After simplifying and factoring out common terms, we arrive at the final expression for the total kinetic energy of the Earth:

Total KE = (1/5) m R² ω² [1 + (5/2)(D Ψ / (R ω))²]

Thus, the correct answer is:

1) MR² ω² / 5 [1 + (Ψ / ω)² + 5/2(D Ψ / R ω)²]

This expression captures both the rotational and translational kinetic energies of the Earth as it rotates on its axis and orbits the Sun, taking into account the relationships between the angular velocities and the distances involved.