A rod of length L is pivoted at one end and is rotated witha uniform angular velocity in a horizontal plane.Let T1 and T2 be the tnesion at the points L/4 and 3L/4 away from the pivoted ends
A.T2 > T1 B.T1>T2
Ans- B
Dear manoj
let mass per unit length of rod is m
and take a strip of lenghth dx at a distance x from the pivoted end
tension in rod is due to centrifugal force in part of rod that is away from the point of interest
so for point at a distance L/4
T1 = limit L/4 to L ∫ (mdx)w2 x
=15/32 mw2L2
For a point at 3L/4
T2 = limit 3L/4 to L ∫ (mdx)w2 x
=7/32 mw2L2
So T1>T2
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