 # A rod of length L is pivoted at one end and is rotated witha uniform angular velocity in a horizontal plane.Let T1 and T2 be the tnesion at the points L/4 and 3L/4 away from the pivoted endsA.T2 > T1        B.T1>T2Ans- B Badiuddin askIITians.ismu Expert
148 Points
12 years ago

Dear manoj

let mass per unit length of rod is m

and take a strip of lenghth dx at a distance x from the pivoted end

tension in rod is due to centrifugal force in part of rod that is away from the point of interest

so for point at a distance L/4

T1  = limit  L/4 to L    (mdx)w2 x

=15/32 mw2L2

For a point at 3L/4

T2  = limit  3L/4 to L    (mdx)w2 x

=7/32 mw2L2

So  T1>T2

Please feel free to post as many doubts on our discussion forum as you can. If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly.

All the best.

Regards,

one year ago
Dear Student,

let mass per unit length of rod is m
and take a strip of lenghth dx at a distance x from the pivoted end
tension in rod is due to centrifugal force in part of rod that is away from the point of interest
so for point at a distance L/4
T1 = limit L/4 to L ∫ (mdx)w2 x
=15/32 mw2L2
For a point at 3L/4
T2 = limit 3L/4 to L ∫ (mdx)w2 x
=7/32 mw2L2
So T1>T2

Thanks and Regards